>>7794613 This belongs in /sqt/ but I'll bite. Since the tangent is negative and cos(b)>0, sin(b)<0. let cos b = c. sin(b) = -sqrt(1-c^2), the negative value. Solve for c in this: tan(b) = -sqrt(1-c^2)/c = -3/4 then evaluate sin (2b) using the double angle identity.
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