Can you prove 3^x is equal to 3^(1-x) using only expoents rules?
You are not allowed to turn it into an equation
I might have not been fully explicit. The exercise says that 3^(1-x)=6 and you have to take 3^x turn it into 3^(1-x) so you can replace it by 6 and calculate whatever expression you have so you can get 1/2
You should only do it using the rules and thats what Im having problems with
You interpreted it right the only problem is that you took the wrong expression. Do the same starting with 3^x
Take this example:
You know that 3^(1-x) = 6. The expression in the example is 3^(2-2x)
3^(2-2x)= 3^((1-x)*2) [rule 3] = 6^2 = 36
What they mean is that it has been worded incorrectly.
A proof that 3^x is equal to 3^(1-x) is a proof that they are equal for ALL x. What should have been asked for is a solution to 3^x = 3^(1-x), or in words:
>Can you find the values of x for which 3^x is equal to 3^(1-x), using only these exponent rules?