Labyrinth riddle. Two girls (1 always lies, the second always teleschermi truth in a room with 2 doors) i remember that there was a pic with 2 more difficulties to solve im looking for this . One was like "any girl does not know anything about other girl existance"
don't know about the other one you're talking about.
but if the girls don't know about each other, can I explain them ? after all, the rule is only 1 question, it doesn't say anything about explanations.
(love the pic)
You can only talk once to the girls and even if you explain her second she would still not see her and She would answer "there are no other girls here" when you try to know about her answers
you're on a game show
there are three doors
behind one of the doors is always a car
behind the second door is always a goat
the third door produces a car 50% of the time and a goat the other 50%
you pick one door without opening it, the host opens one of the other two doors and it's a goat.
is it in your best interest to switch
Actually the way you phrased the question it would be best to not switch.
Probability of choosing a car right away is 1/2. When the host opens the door with a goat, the probability that your door has a car shoots up to 2/3.
>the probability that your door has a car shoots up to 2/3
Probability of getting car if you don't switch: 1/2
Probability of getting car if you switch:
If d3 = car: 1
If d3 = goat: 1/3 * (0 + 1 + 1) = 2/3
Intuitive reason: Host taking out a goat from the two remaining doors increases the chance of the other door having a car. The only bad case is when there's 2 goats in the two unpicked doors, the other cases (1 goat 1 car) are good and make sure the car's left.
The question doesn't make any sense anyways. What if you choose a goat right away and the other two are cars? How is the host supposed to reveal one of the other doors to be a goat?
The question is always of the form "Hey B, if I asked A which door lead to [set outcome], what would he answer?" when you have only one question.
One of the variants was that you were only able to ask A or B if I remember well. In that case you must make your question (which already includes a conditional relationship) conditional to something you can control or at least know if it is true or not, such as removing your clothes.
There was that one... a 40-meter tall tower is in the center of a 200-meter rocky island with a maze of paths. By the dock where you landed there are three paths, and three guards. One always tells the truth, one answers at random, and one always lies. You can ask them one question. Which path do you choose?
The answer is: the central one, and if it goes off the way, just fucking cut across, the tower is perfectly visible from anywhere on the island. But before you go, ask the liar if the answer to your question will be "yes", and watch the asshole squirm.
Tactic: No switch:
Chance you picked the car: 1/3, period. No matter what the host does, your initial choice with its 1/3 chance stands.
Chance you picked the car at first: 1/3. In this case switching is 100% loss, so your chance of LOSS for this case remains at 1/3.
Chance you didn't pick the car: 2/3. Host reveals the goat. Switching means 100% win because the remaining gate has the car (yours doesn't and the revealed doesn't).
In short: In the first scenario you win if you picked the car (at 1/3 chance). In the second scenario you win if you initially picked the goat (at 2/3 chance).
That is how the original Monty Hall problem goes, but whoever posted the problem above added that the third door could either be a goat or a car. The problem changes now, but I don't think this problem can be done unless its rephrased.
Not sure if this is what you are looking for, there is something more than you originally had.
From what I've gattered in the responses the correct way cannot be discovered everytime, Using the monty hall methodology there is a probability of you rulling out someone you should not.
I'm guessing the ideal sceneario is to have both the true and false sisters but it's probabilistic.