Greetings /sci/,
I am not sure if such a simple question warrants its own thread, but I can't find the usual dumb questions thread.
I am asked to prove that the vector space V is a subspace of R^2. V={k(1,2)|k is in R}.
I started off by proving that it is not empty by letting k be 0 and showing that u=(0,0) is in V.
Then I wanted to prove that the set is closed under addition and I got lost. I tried the following:
let u=(k,2k) and v=(nk,2nk) u+v=k(1+n,2(1+n)) and stopped. I feel like the solution is so easy but I can't express it properly.
Thank you in advance.
Seriously nigger? If k1(1,2) + k2(1,2)=(k1+k2)(1,2) and k1+k2 is obviously in R.
ok im retarded. thank you
>>9165642
These fucking aliens come in here, learn our language, steal my fucking job.
Pack of cunts.