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How to solve the int

2015-11-06 18:56:30 Post No. 7642110

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2015-11-06 18:56:30 Post No. 7642110

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I fail to see how the integral over dE should be equal to pi. I've tried multiple subsitution but I can't seem to find it.

Anyone out there that can shed some light on this?

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>>7642110

it is trivial as the book says

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>>7642115

Actually is says elementary..

Can you show me the steps or are you just here to be funny?

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>>7642110

Does anyone has any idea?

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Book and page?

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>>7642163

Mechanics (Volume 1) by Landau en Lifshitz, Third edition.

Page 28.

The chapter, or paragraph, is called "Determination of the potential energy from the period of oscillation"

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>>7642110

Do a substitution to reduce it to the integral

[math]\int_0^1 \frac{\mathrm{d}u}{\sqrt{(1-u)u}}[/math]

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>>7642168

>lifshitz.

Huehuehue.

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>>7642174

Can you make a picture?

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How to solve the int
2015-11-06 19:51:18
Post No.7642224

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>>7642174

What am I doing wrong?

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>>7642224

Am I taking the wrong steps?

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No one here that can help me?

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I don't know about the minus sign you get though senpai

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>>7642515

First of, Thanks for helping!

Doesn't the minus sign come from the change in variables?

And what inverse function comes out of the integral in your case? Can't seem to read it properly.

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>>7642224

You have immaculate and stylish handwriting.

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How to solve the int
2015-11-06 22:37:43
Post No.7642610

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>>7642604

>>

Whenever you're faced with an integral in physics which is in terms of physical quantities, you're first step should almost always be some (linear) change of variables to a dimensionless parameter. Then the resulting integral which just equal some number multiplied by the physical constants, and whether you can solve the integral or not is usually of little importance to the physics. In this case, you have an integral over energy which depends on the two dimensionful energy values alpha (which I'll call a because I'm too lazy to latex) and U.

Now the easiest dimensionless change of variables is a linear one, z, such that z(E=U)=0 and z(E=a)=1, which you can figure out is just given by z = (E-U)/(a-U). Then you end up with a an integral with no parameters which you can look up or solve with a sin(t^2) subsitution.

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>>7642635

Thanks for the advice! I'll try that.

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>>7642635

Works out like a charm!

Thanks again

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