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if i have a wire of (x) length coiled into (y) number of wraps,

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if i have a wire of (x) length coiled into (y) number of wraps, i'll have an impedance (z)

if i add a second identical wire of (x) length and parallel coil the two wires into (y) number of wraps, i'll have an impedance (0.5z)?

now if i cut the length of the wires to (0.5x) and parallel coil the two wires into (y) number of wraps, i'll have an impedance (0.25z)?
>>
>>913728
Yes
>>
>>913739

thank you
>>
>>913728
>>913739
no
>>
>>913728
maybe
>>
>>913728
I don't know
But I use the steam engine coil calculator to find out
>>
>>913728
What kind of coil is this in the pic? Looks more like a spring. Are the windings even insulated from each other?
>>
>>913728
Pretty much so
it will be a bit over (0.25z) due to lead length.
>>
>>913891
It's an e-cig atomizer.
Surface oxidation provides insulation
>>
>>913897
Oh so it's a heater rather than an inductor.
>>
Im an electronician or something
That looks like this
They are Just 2 parallel resistors
That calculates like this:
R1=resistance of 1st coil
R2=resistance of 2nd coil
R=whole resistance
R=(R1√óR2)/(R1+R2)
But don't use different values for R1 and R2 cuz it probably won't vape properly
Also it works on DC so there is no inductance
Sorry for bad English etc. Hope i helped
>>
>>914539
he's talking about impedance, therefore resistance AND reactance
>>
>>914570
... and feeds it from a DC source, making the reactive part irrelevant.
>>
>>914570
The guy up there just said it was for a e-cig atomizer. Hence the DC like >>914573 said.
Even if we were talking about AC, reactance would only be somewhat relevant if the coil had A LOT of turns, or if it were running on a really really high frequency system.

The word "impedance" doesn't imply that the reactive part cannot be zero.
>>
>>914570
You do realise that e-cigs work on DC, and therefore there is NO reactance on coils?
No AC-> no reactance.
Also in that case ressistance=impedance.
Thread posts: 15
Thread images: 1


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