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You should be able to solve this.

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Impossible, an angle must be given

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>>153612299

359º

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>>153612299

360? i seem to remember this from my maths textbook

can't prove it tho lol

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180

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>>153612595

same

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>>153612299

Internal angles of a 5 pointed star always add up to 180 degrees.

Put a pencil on the line from A-D, rotate around A so it aligns A-C, then C-E, E-B, B-D, D-A.

Pencil no lies on the same line, pointing the opposite direction.

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>>153612299

sum of red corner as they are a pentagonal

540x2=1080

sum of blue corner

360x5 - 1080 = 720

sum of A-D corner

180x5 - 720 = 180

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180-(180-u)-(180-v)+180-(180-v)-(180-w)+180-(180-w)-(180-x)+180-(180-x)-(180-y)+180-(180-y)-(180-u)=

=2u+2v+2w+2x+2y+5*180-10*180=

=540*2-5*180=

=1080-900=

=180

Where u,v,w,x,y are the angles inside of the pentagon, which add up to 540.

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>>153613056

But who was the killer?

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>>153613101

Me, after I realised there's a more elegant solution to it, which is adding two triangles and substracting one.

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>>153612839

Oh that's nice

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>>153612299

The shape is a star which has 10 sides which is homogeneous to a decagon. Therefore the problem is equivlent to finding sum of 5 alternating angles on a decagon, which can be proven false by first proving that it's not possible to find sum of opposing angles on a quadrilateral then by induction.

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>>153615909

>can be proven false by first proving that it's not possible to find sum of opposing angles on a quadrilateral

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here you go dude, you should do your own homework Josefumi, this isn't /sci/ ffs

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>>153617331

That's Joshuu's homework. Josuke did it in an instant.

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>>153617656

13 and 0

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>>153617710

The blank space next to A should be labelled 10 if 4 and 6 are overlapping, this leads me to believe that blank space is 0, and the shapes are not as they first appear.

A = 3

B = 0

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>>153619264

Nope, red is 6 because it has 6 sides, if it had that shape it should be labeled 8 instead and 4 should be 6, etc.

10 is simply not labeled, or if it was 0 it should be labeled as 0.

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>>153612299

it's 300°

A°+C° are 2/3s of a triangle, and a triangle's complete angle is 180°.

Same applies to E°+B°.

D is left over as 1/3 of 180°

therefore,

2*(2/3 *180°)+1/3*180° = 300°~~i'm probably talking bullshit here, but it's a round number~~

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>>153620422

2/3 of a triangle can be anything from 1° to 179°, you know?

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>>153620422

The angles of a triangle do add up to 180°, but that doesn't mean all angles are the exact same, otherwise every single triangle would be equilateral. For all we know A° and C° could be only 1° and in that case the remaining angle would be 178°. Same with the other angles.

tl;dr: spoiler is correct

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https://www.youtube.com/watch?v=8xqskiIehfk

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>>153620756

>it's a scalene triangle episode

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>>153612299

It's all triangles.

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>>153617331

>implying /a/ doesnt have 400+ reply threads about math problems every now and again

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Thread images: 10

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