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You should be able to solve this.

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Thread replies: 31
Thread images: 10

File: math.png (141KB, 572x536px) Image search: [iqdb] [SauceNao] [Google]
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You should be able to solve this.
>>
Impossible, an angle must be given
>>
>>153612299
359º
>>
>>153612299
360? i seem to remember this from my maths textbook

can't prove it tho lol
>>
180
>>
>>153612595
same
>>
>>153612299
Internal angles of a 5 pointed star always add up to 180 degrees.
Put a pencil on the line from A-D, rotate around A so it aligns A-C, then C-E, E-B, B-D, D-A.
Pencil no lies on the same line, pointing the opposite direction.
>>
File: file.png (175KB, 567x535px) Image search: [iqdb] [SauceNao] [Google]
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>>153612299


sum of red corner as they are a pentagonal

540x2=1080

sum of blue corner

360x5 - 1080 = 720

sum of A-D corner

180x5 - 720 = 180
>>
File: lCw7u.gif (1MB, 360x360px) Image search: [iqdb] [SauceNao] [Google]
lCw7u.gif
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>>
180-(180-u)-(180-v)+180-(180-v)-(180-w)+180-(180-w)-(180-x)+180-(180-x)-(180-y)+180-(180-y)-(180-u)=
=2u+2v+2w+2x+2y+5*180-10*180=
=540*2-5*180=
=1080-900=
=180

Where u,v,w,x,y are the angles inside of the pentagon, which add up to 540.
>>
>>153613056
But who was the killer?
>>
>>153613101
Me, after I realised there's a more elegant solution to it, which is adding two triangles and substracting one.
>>
>>153612839
Oh that's nice
>>
>>153612299
The shape is a star which has 10 sides which is homogeneous to a decagon. Therefore the problem is equivlent to finding sum of 5 alternating angles on a decagon, which can be proven false by first proving that it's not possible to find sum of opposing angles on a quadrilateral then by induction.
>>
File: shinji.jpg (21KB, 344x313px) Image search: [iqdb] [SauceNao] [Google]
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>>153615909
>can be proven false by first proving that it's not possible to find sum of opposing angles on a quadrilateral
>>
File: IMG_0104.jpg (2MB, 2448x3264px) Image search: [iqdb] [SauceNao] [Google]
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here you go dude, you should do your own homework Josefumi, this isn't /sci/ ffs
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>>153617331
That's Joshuu's homework. Josuke did it in an instant.
>>
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>>
>>153617656
13 and 0
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>>153617656
42
>>
File: solve for x.png (595KB, 1280x738px) Image search: [iqdb] [SauceNao] [Google]
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File: file.png (221KB, 447x307px) Image search: [iqdb] [SauceNao] [Google]
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>>153617710
The blank space next to A should be labelled 10 if 4 and 6 are overlapping, this leads me to believe that blank space is 0, and the shapes are not as they first appear.
A = 3
B = 0
>>
>>153619264
Nope, red is 6 because it has 6 sides, if it had that shape it should be labeled 8 instead and 4 should be 6, etc.
10 is simply not labeled, or if it was 0 it should be labeled as 0.
>>
>>153612299
it's 300°

A°+C° are 2/3s of a triangle, and a triangle's complete angle is 180°.
Same applies to E°+B°.
D is left over as 1/3 of 180°
therefore,
2*(2/3 *180°)+1/3*180° = 300°

i'm probably talking bullshit here, but it's a round number
>>
>>153620422
2/3 of a triangle can be anything from 1° to 179°, you know?
>>
>>153620422
The angles of a triangle do add up to 180°, but that doesn't mean all angles are the exact same, otherwise every single triangle would be equilateral. For all we know A° and C° could be only 1° and in that case the remaining angle would be 178°. Same with the other angles.

tl;dr: spoiler is correct
>>
https://www.youtube.com/watch?v=8xqskiIehfk
>>
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>>153620422
>>
>>153620756
>it's a scalene triangle episode
>>
File: triangles.png (150KB, 770x536px) Image search: [iqdb] [SauceNao] [Google]
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>>153612299
It's all triangles.
>>
>>153617331
>implying /a/ doesnt have 400+ reply threads about math problems every now and again
Thread posts: 31
Thread images: 10


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