What even is the right way to solve it? Algebra? I kind of brute forced it by narrowing it down between 30 and 40. Did some more work but I got 32 this time. 32x3/2=48 so it adds up nicely to 80.
Here's how I did it, cause now I feel stupid.
x=Time for one trip
return trip is 2/3's speed so I reasoned it out to x+(x/3)
Never, because there are no parks in Gensokyo.
I'm not good at math:
So she spent 80 minutes jogging total.
Her total speed would be 5/3. So if I remember the operations, since it'd be 80 = 5/3 (x), you'd have to multiply 80 by 3 and divided it by 5, meaning x = 48, so 2/3 of that would be 32.
So she arrived at the park at 9:48, waited for an hour, left at 10:48 on the dot somehow, and arrived back home at 11:20.
Thank you. Now to never watch Ro-Kyu-Bu again.
Your method is the most correct so far, but you've got the speeds mixed up. She gets to the park faster than she returns, so the trip there should take 32 min and the trip back 48 mins.
Who gives a shit at what time some dumb slut reached the park? Math is fucking dumb.
Ah, you're right. Forgive me, its 1AM; I think I'm allowed a dumb mistake at 1AM