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Will you solve it and bang Kuro after school's out?

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Thread replies: 100
Thread images: 26

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Will you solve it and bang Kuro after school's out?
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I will not solve anything and bang her right there, in front of the whole class
>>
Banging her while solving sounds better.
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>>146086035
Maybe I'll go back to school and learn Maths again, I really want to fuck Kuro.
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>>146086035
I construct the triangle and calculate the angles manually. That's elementary geometry with no trigonometry involved!
>>
a couple of entry-level theorems should do the trick

but really, just ask
>>>/sci/

I wonder what portion of that board would want to fuck Kuro
>>
>>146086035
super easy mate, no trigs needed. Its just literally calculate every angle you can get your hands on, and keep going on until you get it
>>
I want Kuro to teach me algebra instead.
Geometry is for fags.
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>>146086592
Not really, you can't get to the solution only by calculating the angles, since you end up with 4 unknown ones.
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It's not solvable without trig, as proven in other threads.
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>>146086694
Oh, and to elaborate, the 4 angles, by the rules that governs the angles of triangles, for a system with infinite solutions.
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>>146086035
>top left triangle has 50 degrees as an obtuse angle
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>>146086694
Hmmm no. You can get BCA since you know CBA and ABC. Then you get BDC with CBD and BCD. Then you get CED.
And you can get BEA since you know EBA and EAB.

So for BEC, you know know everything but Alpha. Simple substraction and you get it.
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>>146086704
No, it is solvable. You just have to make extra points and lines.
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>>146086819
Explain how you get CED.
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>>146086035

Well I would surely love it if banging girls was as easy as this problem ...
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>>146086962
it just works.
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>>146086035
alpha = ∢ DEA

there, now fuck me
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>>146086972
Brilliant. Why didn't I think of just picking random numbers.
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>>146086972
Just works? Show us steps
>>
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>>146086819
>>
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Here's a more interesting problem.
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>>146087188
now that's my favourite subject
>>
>>146087188
Goat demon with pincers.
>>
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Try this one on for size you hopeless virgins.
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>>146087280
Infinity.
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>>146087280
-1/12
>>
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>>146087318

>he thinks it's infinity and not -1/12
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>>146087280
-1/12 phaggot
>>
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>>146086035

Alright, so
∠CAB = 80
∠CBA = 80
∠C must be 40

∠CAE = 10
∠C = 20
∠AEC must be 150

∠EAB = 70
∠DBA = 60
∠AFB must be 50
∠DFE must also be 50

∠DFE = 50
∠AEC = 150
∠C = 20
∠CDB must be 140
These are the angles for the diamond shaped quadrilateral.

Call ∠CED = X and ∠CDE = Y

20 + X + Y = 180

∠AEC-X = α = 150-X
∠BDC-Y = ∠BDE = 140-Y

(150-X)+(140-Y)+50 = 180

Solve the system and you end up with nonsensical values.
>>
>>146087400
tl;dr, solution is a range of values with the limitation that α cannot exceed 75 degrees
>>
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You're smarter than Homu, right?
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>>146087280
first, we look at the equivalence
zeta(s) = sum(n=1,infinity)1/n^s
and we plug in s = -1 to get
zeta(-1) = sum(n=1,infinity) 1/n^(-1)
=sum(n=1,infinity) n
=1+2+3+4+...

now, we note that the zeta function also satisfies
zeta(s) = 2^s * pi^(s-1) sin(pi*s/2) Gamma(1-s) zeta(1-s)
so we have
zeta(-1) = 2^(-1) * pi^(-1-1) sin(pi*-1/2) Gamma(1--1) zeta(1--1)
=1/2 * 1/pi^2 sin(-pi/2) Gamma(2) zeta(2)

by eulers solution to the basel problem, we have zeta(2) = pi^2/6, so
zeta(-1) = 1/2 * pi^2/6pi^2 sin(-pi/2) Gamma(2)
= -1/12 Gamma(2)
= -1/12 = zeta(-1) =1+2+3+4+...
therefore, by transitivity and symmetry of equality, we have

1+2+3+4+... = -1/12
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>>146087188
Is that the back of the knee?
>>
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>>146087489
is 0 a natural number?
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>>146087280
>>
>>146087730
In some country yes. Mostly no.
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>>146086035
I threw a bunch of algebra at the wall and got 120. Is that correct?
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>>146087400
>>146087761
No.
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>>146087853
Steel weighs more then air, so right, faggot.
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>>146087910
It is right, but not for that reason
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>>146087910
https://www.youtube.com/watch?v=uH0hikcwjIA
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>>146087826
CAG isn't congruent to CAE in your picture. They share one side, no angles.
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>>146088017
Is it because the left acts as like a balloon since the ping pong ball tied down instinctively wants to drag itself up therefore reducing its weight?
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>>146087756
i'll just use the binomial theorem then:
we have:

p is prime
n is natural
prove (1+n)^p-n^p-1 is divisible by p

use the binomial theorem on (1+n)^p to get
(1+n)^p = sum(k=0,p)(p choose k)n^k
p choose k = p!/(p-k)!k!
the first term in that sum is going to be p!/(p-0)!0! n^0 = p!/p! = 1
the last term is going to be p!/(p-p)!p! n^p = n^p
we subtract a 1 and an n^p from the (1+n)^p, so all of the terms are of the form
p!/(p-k)!k! for 0 > k > p
p! by definition is a multiple of p, and because k is never 0 or p, each term is a multiple of p
therefore it is divisible by p

that look right?
>>
>>146087853
The right side, even though the steel ball is attached to a string the water still exerts a buoyant force on it which means the ball exerts a downward force on the water.
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>>146087826
your drawing doesn't even make sense?
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Man i fucking hate when maths starts using letters n shit. Like, maths is just numbers people, no need to complicate things even more. This ain't English.
>>
>>146086035
I'm too dumb for this shit.
Someone give me a common core version of the solution so I feel smart about myself.
>>
>adding every positive integer for infinity gives you a negative fraction

Math is shit.
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>>146088134
You fucking retard, holy shit.
It's just A=1, B=2 all the way to Z=26.
Shit's simple, brah.
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>>146088134
>he doesn't like math
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>>146086035

>end up with some algebra expressions with alpha in them
>excitedly set about simplifying them to get the answer
>0 = 0
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>>146088169
Its just when you look at where it hits the xaxis.
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>>146088036
No, they are congruent. CG bisects angle ACB, so angle ACG = 10 = angle EAC and ACG ~= BCG thus angle GAC = angle CBG = 20 = angle ACE.
angle ACG = angle EAC, angle GAC = angle ACE, and AC = AC.

>>146088123
Not my drawing, I am too lazy to make one so I used the one that other anon post.
>>
>>146088236
>>146087483
When you end up with 0=0 there's technically an infinite amount of solutions.
>>
>>146088277
Or that method simply doesn't work.
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>>146088250
ACG ~= BCG
why?
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>>146088363
AC = BC, GC=GC, angle ACG = angle GCB so triangle ACG ~= triangle BCG
>>
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What a bunch of nerds lmao
>>
>>146088444
pls no bully
pls
>>
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>>146088486
Gimme your lunch money, dweeb
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>>146086035
>tfw forgot everything relate to math after i have finished my university
Damn, and i used to be a little good at math too
>>
>>146087280
It's divergent, there isn't a sum.
>But muh -1/12...
Is mathematically relevant to the series, but not the sum of it. Fucking parrots.
>>
I want Kuro to sit on my face while she creates lesson plans.
>>
>>146088633
then what the fuck is this >>146087594
>>
>>146086035
My maths sucks.
>>
>>146087280
Paradox
Depending on what series rules you decided to use in math -1/12
Dont want to get into details

But lets assume you have an infinitely large bar. Friday nights are the non miss event and people will pay anything to get in and an infinite people will show up. The cover starts at 1 buck and increases by a dollar for each person? So you gonna tell me the owner made a net loss of -1/12 a dollar?
Not of course assuming all the cash went black hole or something.
>>
>>146088669
Zeta function regularization.
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>>146086035
I remember someone saying this was unsolvable
Can anyone confirm it with AutoCAD or whatever?
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>>146090290
No, it is totally solvable. Link to the website with the solution keep being posted. The correct answer keeps being posted. Don't be misled.
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>>146087184
And then you stop since it's unsolvable past that.
>>
>>146088072
>>146087489

surely there's a quicker way to do this?
is it important that p be a prime, and not just a natural > 1?
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>>146087910
More like water is heavier than air.
>>
>>146087280
1+2+3+4+(nothing) =(nothing)

1+2+3+4+-10=nothing

that was easy
>>
>>146086035
Can't I just be friends with her instead.

I used to sort of like math but 2 semesters of garbage teachers kind of put me off of it and I didn't need anymore anyway.
>>
>>146087910
it is more dense, it does not weigh more
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>>146087489
got any of the homu edits?
the more complicated the better
>>
>>146088248
wtf what you said doesnt even make sense, why should I look at the y-axis? And what does that staircase mean? It doesnt even touch the line.
I bet you dont understand the pic either
>>
>>146086035
a is 0 degrees, the triangle is impossible, fuck off.
>>
>>146086035
90* MOTHER FUCKERS, KURO I AM GOING TO DO REALLY NASTY THINGS TO YOU.

It is solveable but only through trial and error.
find the hexagon of e middle point d,c and then solve from there.
>>
>>146098803
It was 20 degree. Just check it with geogebra or something like that. See >>146087826
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Actually the triangle it's quite impossible
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>>146099248
>>
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>>146099009
And a rule was broken, ELEMENTARY MATH ONLY. You can't just draw new lines and be like LOL now figure this mess out. 90 degrees is the answer.
>>
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>>146099248
Actually the stupid there is you
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>>146100139
Show your work. How did you figure out the angles?
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>>146100025
That solution only uses elementary GEOMETRY methods.

>>146100268
It is a simple reconstruction of the figure. There is only one possible configuration.
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>>146086035
sometimes I wonder how did I manage to graduate anyway lol
>>
>>146086035
If I was a degenerate pedophile sure I would
>>
>>146100268
http://thinkzone.wlonk.com/MathFun/Triangle.htm
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>>146086035
>ABD
>80+60+x = 180
>D should be 40
>D in the image is at least 80
>>
>>146104378
If you had ever opened a maths textbook you would know that these diagrams are not to scale.
>>
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>>146087594
Zeta function equals the sum only when Re(s) > 1 you retard rofl.
>>
>>146100139
>>146100268
I'm presuming from that that the answer would probably come about from extending all the line segments out into lines, so that equivalent angles can be deduced from the resulting web.

>∠DBE equals 20 degrees
>a equals 20 degrees
I wonder if that could have been deduced in some way.
>>
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>>146086229
Anon are you me?
>>
>>146087730
No Patrick, mayonnaise is not an instrument.
>>
>>146088444
except all these nerds are wrong
Thread posts: 100
Thread images: 26


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