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Can someone help me with my test corrections?
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Can someone help me with my test corrections?
>>
>>55563
I don't know how the answer can't be C. Ask some friends and see what they got. Your teacher might have just screwed up.
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>>55563
If you use the pictures shown (I can't tell if they are really similar) then
AC:EG = 11/35 (answer C).

If you use the order of the vertices for the correspondence and disregard the pics except for the measurements then the sides AB, BC, AC correspond to the sides EF, FG, EG, so the ratio AC:EG correspond to the scaling factor, which can only be determined by EF and the corresponding side AB. Therefore
AC:EG = AB:EF = 5/35 = 1/7 (answer A).

But I still think that answer C is correct.
>>
>>55603
Yeah, I'm pretty sure it has to do with the order of the vertices. Although the diagram is really shitty and misleading, the definition of similarity is that corresponding sides are in proportion and corresponding angles are congruent.

Although the diagram seems to imply BC corresponds to EF,
since similarity is defined in the above way, we have to conclude BC actually corresponds to FG (based on the order).

In this case, since we know AC:EG = AB:EF (by the aforementioned definition of similarity),
we find that AB:EF = 5:35 = AC:EG = 1:7.
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