[Boards: 3 / a / aco / adv / an / asp / b / biz / c / cgl / ck / cm / co / d / diy / e / fa / fit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mu / n / news / o / out / p / po / pol / qa / qst / r / r9k / s / s4s / sci / soc / sp / t / tg / toy / trash / trv / tv / u / v / vg / vip /vp / vr / w / wg / wsg / wsr / x / y ] [Search | Home]
Would anyone be able to shed some light on...
If images are not shown try to refresh the page. If you like this website, please disable any AdBlock software!

File: Screenshot_2.jpg (13 KB, 769x127) Image search: [iqdb] [SauceNao] [Google]
13 KB, 769x127
Would anyone be able to shed some light on the method for how one would go about doing this?
>>
>>55152
9k=3+k
>>
>>55152
The function is defined in two parts. In order to make it continuous, you just have to make the two parts meet.

They split in x=3.

So, in x=3, the two parts need to have the same value.

Which means that:
k*32=3+k

k=3/8
>>
>>55165
fixing :

k*3^2 = 3 + k
9k = 3 + k (as in >>55158)
8k = 3
k = 3/8
>>
Thank you