r u supyeror ly intelgent enoug??? proof it...

maybe write the problem correctly first and I will pretend to do it while the thread dies

>>8543810
>"quadratic" function
>has degree n
why?

>>8543810
Why is penmanship not a thing that's taught in school anymore? I find it really pathetic when I see someone who is 15 or older have garbage penmanship. You print about as good as a kindergartener.

>>8543810
>the 2nd term
OP you fucking moron

>>8543810
>n^(x-1)
>quadratic

>>8543810
Later in your problem you write x = n, replace x with n and the answer basically slaps you in the face. Pull out n^n as a common factor. How many n^n's are there? n+1, because you begin counting from n^0 to n^n.

>>8543810
Not gonna bother to tex on your shitty thread.

Rewrite f(x) as the sum from k=0 to k=n of (n^k)*x^(n-k)

then every term of f(n) is equal to (n^k)*n^(n-k) = n^(k+n-k) = n^n

so f(n) = the sum from k=0 to k=n of n^n

because n is a constant, not dependant on k we can apply the most elementary theorem about sums,

f(n) = (n+1)*(n^n)