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I don't think $1^2 = 1$;...
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I don't think $1^2 = 1$; I think $1^2 = 2$.

If $1^2 = 1$ then $1 \cdot$ has no effect.

How can rationals be countable if real numbers are uncountable?
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>>7852069
Fuck off Howard.
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1^2 =/= 2 because sqrt(2)^2 = 2
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X^0 +1 = Prime number

All natural numbers are prime
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>>7852103

$1^2 \neq 1$ because $(-1)^2 = 1$
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What should $1 \cdot$ be then ? The number of offspring when you fuck a goat ?
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>>7852112

$2^2 = 4$ so 4 is not prime
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>>7852069
Your dick doesn't have an effect either.
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>>7852069

>terrence howard meme

>Salvia officinalis
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x^0= 1

1^2 = (x^0)^2
1^2= x^(2*0)
1^2 = x^0
1^2 = 1

I'm just an engineer student tho, not very good with proofs, so this may just be bullshit.
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>>7852103
>1^2 =/= 2 because sqrt(2)^2 = 2

So $\sqrt{2} = 1$. You wouldn't say that $2^2 \neq 4$ because $(\sqrt{4})^2 = 4$
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>>7852069
I don't think 4+0=4, I think 4+0=5.
If 4+0=4 then +0 has no effect.
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>>7852114
Sure, but:

[eqn]
\sqrt{1} = \pm 1
[/eqn]

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>>7852112
2^0 +1 =2 which is prime
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>>7853293

But 0 is just nothing, so of course adding nothing has no effect.
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>>7853272
(4^(1/2))^2 = 4^(2/2) = 4

Yes you can, tard
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>>7853598

$\sqrt{2}^2 = 2$
$\sqrt{4}^2 = 4$

If $2^2 = 4$ then $\sqrt{4} = 2$.

IF $1^2 = 2$ then $\sqrt{2} = 1$