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You are currently reading a thread in /sci/ - Science & Math

You are currently reading a thread in /sci/ - Science & Math

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Hello /sci/!

I've just now discovered my love for math, and just started to tackle antiderivatives. Please bare in mind that i have no prior knowlage of math exept for the basics. I was hoping you could help me fuel this newly found love. I'm currently stuck with this one, could you help me understand the process and how to reach the result?

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>>7809578

we use the legendary plug and chug technique

someone should make a flow chart but in anycase:

1) observe that his is a fraction with a 4th degree polynomial in the denominator. therefore the flowchart say partial fraction that bitch

-(x + 1)/(x^2 + 1) + 1/x + x^(-2)

now we may integrate these 3 components seperately by plug-and-chugging them into our already known antiderivative patterns:

1/x => ln(x)

x^(-2) => -x^(-1)

-(x + 1)/(x^2 + 1) => -ln(x^2+1) + atan(x)

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testingczs

[math]x = e^{x}[/math]

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[math]\frac{x+1}{x^4 + x^2} = \frac{x}{x^4 + x^2} + \frac{1}{x^4 + x^2} = \frac{1}{x^2(x + 1)} + \frac{1}{x^2(x^2 + 1)} [/math]

Now comes the tricky part.

find A, B such that

[math]

\frac{1}{x^2(x + 1)} = \frac{A}{x^2} + \frac{B}{x+1}

[/math]

Then integrate.

Do the same for the second term.

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>>7809578

Partial fraction decomposition

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Thanks for the replies!

After allot of work i got this, can anyone tell me if i got it right?

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>>7809726

oops, forgot the image...

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>>7809730

>missing the constant

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>>7809739

That is also something i never quite understood, why add a constant? if you derivate it's going to disapear... This might be a really dumb question :/

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>>7809748

Anon was joking; you got the joke.

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>>7809748

Cause a family of functions like

2x+56 or 2x -9771

Hace the same derivate

So its the same with antiderivates

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>>7809748

> if you derivate it's going to disapear

thats why we need it. why would you let the constant be zero, theres no reason for that

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>>7809748

If you integrate, you can build the function on a cartesian graph, but you cant fully predict its position to the y axis.

When you derive, it goes away because you are describing other aspects of f(x) like its curvature and instantaneous rate of change.

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>>7809748

in mathematics, you'rere usually looking for the most general answer there is. by computing the antiderivative, you're answering "find ALL functions with this derivative" rather than "find SOME function with this derivative". it can be proven that two differentiable functions have the same derivative if and only if they differ by a constant (it's a very easy proof and I suggest you try it yourself). therefore by adding a constant as a parameter, you're actually describing every function with the wanted derivative.

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>>7809882

I see, thank you for the explanation!

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>>7809959

Trying to search for general answer anywhere outside of mathematics is a lethal approach to the intelligence problem.

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>>7809748

Initial/boundary conditions need to be satified.

Equations aren't there to just look pretty.

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Anyone to help me with this? Also an antiderivative.

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>>7809654

There is a mistake in your maths. Don't skip steps anon, you aren't impressing anyone.

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>>7810686

once again we use the legendary plug and chug technique

observe that there is a function and its derivative (if you cannot make these observations yet you have learn more plug-n-chug formulae).

we simply sub the function:

u=arctg(t)

du = 1/(1+t^2) dt

=>integrate u du = 0.5u^2 + k

=>sub t back in: 0.5arctg^2(t) + k

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>>7809654

((x)(x+1))^-1 not ((x^2)(x+1))^-1

also, partial fractions don't work like that for the second term.

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