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e=x^(x)
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sci, how can I find x in this equation? e=x^(x) pic unrelated
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>you dont
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x^x = e^(log(x^x)) = e^(x·log(x))

=>

log(x) == 1/x

and now you gotta check the productlog
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why don't you just see where x^x=e in a graph?
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>>7806878
Too inexact
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>>7806862
[eqn] e=x^x \implies 1-x \ln (x) = 0 [/eqn] Then use Newton's method and you get that $x \approx 1.76$ or if you don't like that then use Lamberts W-function then [eqn] x = e ^{W(1)} [/eqn]