Please Obi-sci-kenobi. You're my only hope.

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You are currently reading a thread in /sci/ - Science & Math

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Please Obi-sci-kenobi. You're my only hope.

I know this is "homework help question", but I really want to learn the method on how to solve matrices.

This is just one of my problems, but I can't seem to solve it with elementary row operations. An online calculator can solve it, but I can't figure it out. Is the system inconsistent?

The last column is obviously the right side of the equation. Everything to the left are obviously the coefficients.

2 1 3 2 0 1

0 0 1 1 2 1

0 0 0 0 3 0

I managed to simplify it to this:

2 1 1 0 0 0

0 0 1 1 0 1

0 0 0 0 1 0

but I can't figure out what to do from here.

>>

>>7800858

a solution:

[math] \begin{bmatrix} 0 \\ 0 \\ 0 \\ 1 \\ 0 \end{bmatrix} [/math]

>>

>>7800858

>2 1 1 0 0 0

>0 0 1 1 0 1

>0 0 0 0 1 0

2 1 1 0 0 -1

0 0 1 1 0 1

0 0 0 0 1 0

>>

>>7800858

>2 1 1 0 0 0

>0 0 1 1 0 1

>0 0 0 0 1 0

row-1 looks incorrect, should be

2 1 2 1 0 0

>>

>>7800883

Yeah you're right

But now what?

>>

>>7800858

>how to solve matrices

Can we stop blindly throwing the word "solve" around anytime there's math involved?

>>

>>7801042

At the bottom I referred to equations, implying that this is an augmented matrix

I am trying to solve a system of equations

>>

>>7800858

The relevant matrix is 3x5, rank 3. You will have a 2 dimensional space of solutions. Find one solution p, and a basis for the kernel of the matrix k1,k2, the solutions will be p + c1 k1 + c2 k2.

Or something.

>>

>>7801985

To find a particular solution, consider the first two rows, columns 2

and 3 (plus augmentation):

1 3 1

0 1 1

A solution is [-2,1]. So for the original, [0,-2,1,0,0] is a solution.

Now find the kernel.

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