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Did I break math?
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Did I break math?
>>
>>7791713
that epic feel when you draw a line i units long
>>
>>7791713
You cannot of a length of "i". Using the isomorphism $\mathbb{C} \cong {\mathbb{R}^2}$ you could roughly equate $i$ with the 2-tuple $\left( {\begin{array}{*{20}{c}} 0 \\ 1 \end{array}} \right)$. This is not a quantity that you can define as a length. The best you could do is a define as a length as the modulus of i, which is just 1.
>>
>>7791728
>>7791736
phew thanks
>>
>>7791713
length is defined as a real number, complex length does not exist. therefor your triangle cannot exist.
>>
>>7791713
no you're fucking retarded
let's say
a+bi=z
and
abs(z)=sqrt(a^2+b^2)
so
i==1*i==b*i for b=1 ; a=1
then
abs(z)=sqrt(1+1) => abs(z)=sqrt(2)

grab a book and stop asking retarded questions

what's next? drooling over e^(pi*i)=-1? for fuck's sake
Thread replies: 6
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