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hey, /sci/, i have a question about the otto...
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hey, /sci/, i have a question about the otto cycle (applied thermodynamics exam soon). If it is symplified like pic related, is the work done by any single transformation int(pdv) or -int(vdp)? The total work in both cases is equal (same area on p-v diagram). I know that -vdp is for flows through an open system, and a typical cylinder IS an open system, but at the same time there is moving boundary work and you can't realy use a control volume. Help pls
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>>7788196
pls respond
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>>7788274
an ideal otto cycle, is asummed to be a closed system, because the energy transfer happens in a fixed mass or control mass. then, by the enthalpy definition, dh=du + pdv + vdp, but the latter terms become zero, because is a closed system. given this, using first law, and having in mind that the expansion and compression are adiabatical processes (q=0), then the work is defined by means of the internal energy changes. hope this helps.
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>>7788378
I always thought this was called the Carnot cycle, but yes this anon is right. Also, the entropy for the system will be 0, which I'm sure you'll learn soon.
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>>7788378
thanks, cleared up my ideas a bit
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