[Boards: 3 / a / aco / adv / an / asp / b / biz / c / cgl / ck / cm / co / d / diy / e / fa / fit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mu / n / news / o / out / p / po / pol / qa / qst / r / r9k / s / s4s / sci / soc / sp / t / tg / toy / trash / trv / tv / u / v / vg / vip /vp / vr / w / wg / wsg / wsr / x / y ] [Search | Home]
4Archive logo
is there something i'm missing in my...
If images are not shown try to refresh the page. If you like this website, please disable any AdBlock software!

You are currently reading a thread in /sci/ - Science & Math

Thread replies: 23
Thread images: 1
File: Picture 23.png (50 KB, 801x361) Image search: [iqdb] [SauceNao] [Google]
Picture 23.png
50 KB, 801x361
is there something i'm missing in my textbook? why the hell is y=1? and not -1?
>>
does Z2 not denote a field of mod 2, in which case you would get (y + 1) mod 2 = 0
?
>>
>>7775561

Isn't Z_{2} the quotient group Z/2Z, so that 1=-1 (mod 2)?
>>
>>7775582
this
add the two equations together as stated in the solution

2x + y + 2z = 1

2x = 0 in Z2
2z = 0 in Z2
Therefore you're left with y=1
>>
>>7775587
Given that the first equation is y + (x + z) = 0

and the second is x + z = 1

then why isn't the first equation, when substituted, y + 1 = 0

and then why isn't y = -1?
>>
>>7775590
Probably because the integer -1 is not an element of this field. Look again to the way they have defined it. This is consistent with the fact that the text shows there are only 2 solutions, and not infinite ones.
>>
>>7775590
y+1=0 is correct

that means you have to look for the inverse element of 1 for the operation + in Z2

and that is the element 1

there is no such thing as substraction, only addition

you can also start from y+1=0, and add 1
y+0 = 1
>>
>>7775599
>>7775613

You guys are right. I misunderstood the question.
>>
Is this a troll post? The only real number solution here is y = -1

If you input the numbers from that 'solution', you get 2 for both equations which are obviously false. The actual solution is x = 1, y = -1, z = 0.
>>
do not respond to that last post
>>
>>7775642
>begins troll post by asking if another post is a troll post
I see you there, troll
>>
>>7775642
>>7775656
>>7775646

huehuehue, ok I solved it for realsies. I think this is beyond what OP is studying but here is the real answer:

x = -t
y = -1
z = t + 1
>>
>>7775682

That screenshot is still wrong as fuck though. The proposed points do not fit the first equation at all.
>>
>>7775721
they do...
>>
>>7775725

Really? 1 + 1 + 0 = 2, 0 + 1 + 1 = 2. That shit is nonsense. They only fit the second equation but not the first. The other answer:

x = -t
y = -1
z = t + 1

is correct.
>>
>>7775732
there is no 2 in [math]\mathbb{Z}_2[/math], only the classes 0 and 1
>>
Oh shit, I'm dumb, I didnt even read that shit.. That is what booze does to you I guess.
>>
>>7775721
You are a fucking idiot.
>>
>>7775768

shhhh don't tell them that.
>>
>>7775768
Well, technically 2 is in [0].
>>
Ive never seen before a math problem of this kind, what is the field?
>>
>>7775934
Linear Algebra
>>
>>7775934
[math]\mathbb F_2 [/math] :^)
Thread replies: 23
Thread images: 1
Thread DB ID: 418131



[Boards: 3 / a / aco / adv / an / asp / b / biz / c / cgl / ck / cm / co / d / diy / e / fa / fit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mu / n / news / o / out / p / po / pol / qa / qst / r / r9k / s / s4s / sci / soc / sp / t / tg / toy / trash / trv / tv / u / v / vg / vip /vp / vr / w / wg / wsg / wsr / x / y] [Search | Home]

[Boards: 3 / a / aco / adv / an / asp / b / biz / c / cgl / ck / cm / co / d / diy / e / fa / fit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mu / n / news / o / out / p / po / pol / qa / qst / r / r9k / s / s4s / sci / soc / sp / t / tg / toy / trash / trv / tv / u / v / vg / vip /vp / vr / w / wg / wsg / wsr / x / y] [Search | Home]

All trademarks and copyrights on this page are owned by their respective parties. Images uploaded are the responsibility of the Poster. Comments are owned by the Poster.
This is a 4chan archive - all of the shown content originated from that site. This means that 4Archive shows their content, archived. If you need information for a Poster - contact them.
If a post contains personal/copyrighted/illegal content, then use the post's [Report] link! If a post is not removed within 24h contact me at [email protected] with the post's information.