Hi sci, I bet you can't tell what went...

Images are sometimes not shown due to bandwidth/network limitations. Refreshing the page usually helps.

You are currently reading a thread in /sci/ - Science & Math

You are currently reading a thread in /sci/ - Science & Math

Thread images: 1

Hi sci, I bet you can't tell what went wrong. PIC related

>>

>>7765541

Termen =terms

Differentieren = derivative

>>

>>7765541

You forgot to differentiate "n terms" which is another n-dependency.

>>

i like how from 2n=n you were able to conclude 2=1 rather than n=0

>>

>>7765547

The initial statement holds for all n.

>>

x=5

take derivative of both sides

1=0

hurr durr

>>

good thread

>>

>>7765559

good bump

>>

Professor approved

>>

>>7765561

>underlining vectors

wew

>>

>>7765561

The book uses bolded symbols for vectors

>>

>>7765541

confusion of differentiation of a discrete variable with a real valued continuous one, implied by "n terms" which is not possible for non natural number values

>>

[eqn] n^2 = \underbrace{n + n+ \dots + n}_{n~ \text{termen}} [/eqn]

differentieren

[eqn]2 n = \lim_{h \to 0} \frac{\underbrace{(n+h) + (n+h) + \dots + (n+h)}_{n+h~ \text{termen}} - \underbrace{n + n+ \dots + n}_{n~ \text{termen}}}{h}[/eqn]

[eqn]= \lim_{h \to 0} \left( \frac{\underbrace{h + h + \dots + h}_{n~ \text{termen}}}{h} + \frac{\underbrace{(n+h) + (n+h) + \dots + (n+h)}_{h~ \text{termen}}}{h} \right)[/eqn]

[eqn]= \lim_{h \to 0} \left(\underbrace{1 + 1 + \dots + 1}_{n~ \text{termen}} + \frac{h (n+h)}{h} \right)[/eqn]

[eqn] = \lim_{h \to 0} \left(n + (n+h) \right) [/eqn]

[eqn] = 2n [/eqn]

>>

>>7765583

>(n+h)+...-n+n+...

>>

>>7765549

so ?

>>

>>7765541

n^2 = 1+1+...+1 (n^2 times).

Differentiate:

2n = 0.

n=1:

2 = 0.

>>

>>7765596

So you can't arrive at a restriction on n.

Thread images: 1

Thread DB ID: 377885

All trademarks and copyrights on this page are owned by their respective parties. Images uploaded are the responsibility of the Poster. Comments are owned by the Poster.

This is a 4chan archive - all of the shown content originated from that site. This means that 4Archive shows their content, archived. If you need information for a Poster - contact them.

If a post contains personal/copyrighted/illegal content, then use the post's