>>26311913 >>26311976 two opposite sides of a rectangle have to be the same length, so you know the other two sides are also 3y+2 and 2y, respectively. add up all the sides, and you'll get 10y+4. you're given the perimeter, so you know 10y+4 = 124. solve for y and then plug the value of y into the formula for segment ab
>>26312087 Martin Shrekeli is the Muhammad Ali of business, he started ffrom the ground up with only $1.00 in his pocket, he used this to buy a pack of gum, then sold each stick on the street corner at 15c each, making $3.00 a pack, soon he moved on to larger ticket items including buying intellecual property including the cures to cancer and herpes (which he destroyed, because curing cancer will increase lifespans to an unsustainable level, carbon-wise, and the herpes cure because he wants to know who the whores are) he himself remains a virgin because he's saving himself for marriage, and he refuses to marry until he finds a woman who equals him in every way, which is proving difficult. Also he is a known mathematical genius who has proced many theorems including the Barbsberry Problem and Gray Space. He also has been known to brag about his math skills on 4chan
We know that the perimeter of a rectangle is the sum of all its sides We know the CB side is 2y long We know the AB side is 3y +2 long We know the perimeter = 2(CB) + 2(AB) from the definition of a rectangle We know the total perimeter = 124
therefore: 124 = 2(2y) + 2(3y+2) >distribute parentheses 124 = 4y + 6y + 4 >combine like terms 124 = 10y + 4 >subtract 4 from both sides 120 = 10y >solve for y by dividing both sides by 12 y = 12
we've found y, now we just need to plug it in for AB AB = 3(12) + 2 AB = 36 + 2 AB = 38
Thread replies: 19 Thread images: 2
Thread DB ID: 496528
All trademarks and copyrights on this page are owned by their respective parties. Images uploaded are the responsibility of the Poster. Comments are owned by the Poster.
This is a 4chan archive - all of the shown content originated from that site. This means that 4Archive shows their content, archived. If you need information for a Poster - contact them.
If a post contains personal/copyrighted/illegal content, then use the post's [Report] link! If a post is not removed within 24h contact me at firstname.lastname@example.org with the post's information.