Hey electronics /diy/ers. I was just looking at some simple circuits, and theres just one thing I don't really understand about the operation of a basic astable or monostable 555 circuit.
This guy gives a good run-down here: http://pcbheaven.com/wikipages/555_Theory/
Scroll down to "Up and down in 4 steps!".
What I don't understand is this. When the capacitor is fully charged, and it is looking for the least resistive path to ground (see pic), why does it seem to discharge "backwards", rather than just discharge to the ground path directly below it?
Maybe there is something about capacitor theory that I'm missing?
If you take a capacitor apart, you'll see it's made of two electrodes separated by an insulator.
DC cannot cross the insulating dielectric of a capacitor, so whatever charge is in an electrode can only discharge from that same electrode. It can't pass to the other one and discharge through it.
At least not in an ideal capacitor. Real-world capacitors "leak" because the dielectric is not a perfect insulator.
Hello fellow diy electricians
i thought my understanding of electrical circuit illustrations was above average.
But when i tried to connect this wireless switch/receiver to my living-room lamp it does not work. That is to say; i can either switch the light on or i can switch it to flickering.
>inb4 leaving the light on all the time
So my question is;
Doesnt the dot where the horizontal N&L line meet the vertical L1&N line mean a joint/connection?
Sorry for bad English here.
Neither English nor electrical terms are my strong sides.
1) Make sure you're actually switching the live, not the neutral
2) Try it with a Tungsten bulb and see what happens
LED bulbs flickering when they're supposed to be off is a pretty common complaint.
ah, it might be the bulbs,
i doubt the electrician changed thee color of L&N when he did the wires, but ill try.
the dots on the drawing is a connection then.
tnx for the tip
i use 3xled 200ml 3w in my ikea lamp now. so i will have to change that then. (this is european 220-240v)